---
title: "Amps to kW Calculator"
description: "Convert amps to kW for single-phase and three-phase loads. Formula, worked example, and what a clamp meter can and cannot tell you about real power."
standard: "P = √3 × V × I × PF / 1000"
source: "https://energycalchq.com/tools/amps-to-kw"
---

You have a clamp meter reading and you want to know what the load is actually consuming. That conversion needs the voltage and the power factor, and without the power factor the honest answer is a range rather than a number.

## The formula

For a balanced three-phase load:

```
P = (√3 × V × I × PF) / 1000
```

And for single-phase:

```
P = (V × I × PF) / 1000
```

Where `I` is the measured line current in amps, `V` is voltage in volts, `PF`
is power factor, and `P` is real power in kW.

Drop the power factor and you have not calculated kW at all — you have
calculated **kVA**, apparent power. That distinction is the whole of this
page.

## A worked example

A clamp meter reads 72.8 A on one line of a 415 V three-phase motor circuit,
and the motor's power factor is 0.86:

```
P = (1.732 × 415 × 72.8 × 0.86) / 1000
P = 45,000 / 1000
P = 45.0 kW
```

Without the power factor, the same reading gives 52.3 kVA. The 7.3 kVA
difference is not consumption — it is reactive current sloshing back and forth
between the supply and the motor windings, doing no work but occupying the
cable all the same.

## What a clamp meter can and cannot tell you

A clamp ammeter measures current. It does not measure power factor, and it
cannot infer it. So converting its reading to kW always involves an
assumption, and the size of that assumption is worth knowing:

| Assumed PF | 72.8 A at 415 V three-phase reads as |
| --- | --- |
| 1.0 | 52.3 kW |
| 0.9 | 47.1 kW |
| 0.85 | 44.5 kW |
| 0.8 | 41.9 kW |
| 0.7 | 36.6 kW |
| 0.5 | 26.2 kW |

That is a spread of 26 kW on one meter reading. If the number matters — for
billing, for an energy audit, for verifying a supplier's claim — measure the
power factor rather than assuming it. A power quality meter or a decent
three-phase energy meter reads true kW directly, and both are cheaper than
being wrong about the size of a transformer.

Where an assumption is unavoidable, the load type narrows it usefully:

- **Heaters, incandescent lighting, resistive elements** — PF is 1.0 or close
  enough. The current reading converts directly.
- **Motors at full load** — 0.85 is a reasonable central estimate.
- **Motors lightly loaded** — this is where estimates fall apart. A motor at
  25 % load can sit at 0.4 to 0.5 PF while still drawing 40 % of its full load
  current.
- **Modern electronics with active PFC** — 0.95 upward.
- **Older switch-mode supplies, small UPS units** — 0.6 to 0.7, and the
  current is distorted enough that a non-true-RMS meter will read low as well.

## Check for balance before you multiply by three

The three-phase formula assumes a **balanced** load — equal current in all
three lines. Real installations are frequently not balanced, particularly
where single-phase loads have been added to a three-phase board over the
years.

Clamp all three lines. If they read 72 A, 71 A and 74 A, the load is balanced
and the formula holds. If they read 90 A, 55 A and 70 A, it does not: you are
looking at three separate single-phase loads that happen to share a board.
Calculate each phase separately and add them:

```
P = (V_LN × I₁ × PF₁ + V_LN × I₂ × PF₂ + V_LN × I₃ × PF₃) / 1000
```

using the line-to-neutral voltage, 240 V on a 415 V system.

Unbalance matters beyond the arithmetic. It puts current in the neutral,
heats the transformer unevenly, and on a motor, even 2 % voltage unbalance
produces enough negative sequence current to raise winding temperature
noticeably.

## True RMS, and why the cheap meter reads low

If any part of the load is electronic — VFDs, LED drivers, computer supplies,
UPS units — the current waveform is not a sine wave. It is peaky, drawn in
pulses at the top of the voltage waveform.

An averaging meter, which most inexpensive clamps are, is calibrated to give
the right answer for a sine wave and reads **low** on a distorted one,
sometimes by 20 to 40 %. A true RMS meter reads the heating value of the
current correctly whatever its shape.

For any measurement that will feed a cable size, a breaker rating or a
transformer loading calculation on a modern installation, use a true RMS
instrument. The [harmonic distortion loss
calculator](/tools/thd-losses) covers what that distortion costs once it is
in the cable.

## Amps to kW at 415 V, three-phase

At 0.85 power factor, which is a fair assumption for a mixed motor load:

| Amps | kW at PF 0.8 | kW at PF 0.85 | kW at PF 0.9 |
| --- | --- | --- | --- |
| 5 | 2.9 | 3.1 | 3.2 |
| 10 | 5.8 | 6.1 | 6.5 |
| 16 | 9.2 | 9.8 | 10.4 |
| 20 | 11.5 | 12.2 | 12.9 |
| 25 | 14.4 | 15.3 | 16.2 |
| 32 | 18.4 | 19.6 | 20.7 |
| 40 | 23.0 | 24.4 | 25.9 |
| 50 | 28.7 | 30.5 | 32.3 |
| 63 | 36.2 | 38.5 | 40.7 |
| 80 | 46.0 | 48.9 | 51.8 |
| 100 | 57.5 | 61.1 | 64.7 |
| 125 | 71.9 | 76.4 | 80.9 |
| 160 | 92.0 | 97.8 | 103.5 |
| 200 | 115.0 | 122.2 | 129.4 |
| 250 | 143.8 | 152.8 | 161.7 |
| 315 | 181.2 | 192.5 | 203.8 |
| 400 | 230.1 | 244.5 | 258.8 |

## Turning kW into money

Once you have kW, the bill follows from running hours:

```
Units per month = kW × hours per day × days
```

That 45 kW motor running 8 hours a day, 26 days a month, consumes 9,360 kWh —
and at ₹8 a unit, ₹74,880 a month. Which is worth knowing before deciding
whether a more efficient replacement pays for itself. The [electricity bill
calculator](/tools/energy-cost) handles the slab structure that most Indian
tariffs actually use, and the [home load
calculator](/tools/load-calculator) works from appliance wattage.

## Common mistakes

**Reporting kVA as kW.** Multiplying volts by amps gives apparent power.
Real power needs the power factor as well. Bills are in kWh, so this error
inflates a consumption estimate by however far the power factor sits below 1.

**Using 240 V in the three-phase formula.** Use the line-to-line voltage —
415 V — with √3. The 240 V phase voltage belongs only in the per-phase
version of the calculation.

**Clamping one line and assuming balance.** Check all three before trusting
the multiplication.

**Reading a starting current as a running current.** A motor pulls six to
eight times full load current at start. Let it settle before reading.
